(1/sin^2x)(2cosx-1)=0

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Solution for (1/sin^2x)(2cosx-1)=0 equation: 


1*x^4-(10*x^3)+38*x^2-(64*x)+40 = 0

(-1/4)*x-8 = -16

ln((x^4-12)/x)

-7/b = 4

ln((x^11)/5)

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